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If a total force exerted by water in a container with a bottom area of 2 square meters is 450 newtons, what is the pressure in the container?

A. 0.900 kPa
B. 0.225 kPa
C. 0.575 kPa
D. 0.300 kPa

Answer :

To solve this problem, we need to find the pressure exerted by the water in the container. We have the total force and the area of the container's bottom.

1. Identify the known values:
- Total force exerted by water: 450 newtons
- Bottom area of the container: 2 square meters

2. Understand the formula to calculate pressure:
- Pressure is calculated using the formula:
[tex]\[
\text{Pressure (in pascals, Pa)} = \frac{\text{Force (in newtons, N)}}{\text{Area (in square meters, m}^2)}
\][/tex]

3. Calculate the pressure in pascals (Pa):
- Substituting the known values into the formula gives:
[tex]\[
\text{Pressure} = \frac{450 \, \text{N}}{2 \, \text{m}^2} = 225 \, \text{Pa}
\][/tex]

4. Convert the pressure from pascals to kilopascals (kPa):
- Remember that 1 kilopascal (kPa) is equivalent to 1000 pascals (Pa).
- To convert 225 pascals to kilopascals:
[tex]\[
\text{Pressure in kPa} = \frac{225 \, \text{Pa}}{1000} = 0.225 \, \text{kPa}
\][/tex]

5. Select the correct answer:
- Based on these calculations, the pressure exerted by the water is 0.225 kPa.

Thus, the best answer is Option B: 0.225 kPa.

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