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Answer :
First, note that Liliana surveyed a total of [tex]$20$[/tex] seventh-grade students.
Next, we determine the number of students who used their computers. Since a student is considered to have used a computer if they spent more than [tex]$0$[/tex] hours, we count all the students whose reported hours are greater than [tex]$0$[/tex]. Out of the [tex]$20$[/tex] data values, only [tex]$2$[/tex] of them are [tex]$0$[/tex]. This means the number of students who used their computers is
[tex]$$
20 - 2 = 18.
$$[/tex]
Now, the ratio of the number of students who used their computers to the total number of students is
[tex]$$
\frac{18}{20}.
$$[/tex]
To simplify this fraction, divide both the numerator and the denominator by their greatest common divisor, which is [tex]$2$[/tex]:
[tex]$$
\frac{18 \div 2}{20 \div 2} = \frac{9}{10}.
$$[/tex]
Therefore, the ratio is
[tex]$$
\boxed{\frac{9}{10}}.
$$[/tex]
Next, we determine the number of students who used their computers. Since a student is considered to have used a computer if they spent more than [tex]$0$[/tex] hours, we count all the students whose reported hours are greater than [tex]$0$[/tex]. Out of the [tex]$20$[/tex] data values, only [tex]$2$[/tex] of them are [tex]$0$[/tex]. This means the number of students who used their computers is
[tex]$$
20 - 2 = 18.
$$[/tex]
Now, the ratio of the number of students who used their computers to the total number of students is
[tex]$$
\frac{18}{20}.
$$[/tex]
To simplify this fraction, divide both the numerator and the denominator by their greatest common divisor, which is [tex]$2$[/tex]:
[tex]$$
\frac{18 \div 2}{20 \div 2} = \frac{9}{10}.
$$[/tex]
Therefore, the ratio is
[tex]$$
\boxed{\frac{9}{10}}.
$$[/tex]
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