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A toy rocket is shot vertically into the air from a launching pad 7 feet above the ground with an initial velocity of 72 feet per second. The height h, in feet, of the rocket above the ground at t seconds after launch is given by the function h(t)=-16 t²+72 t+7. How long will it take the rocket to reach its maximum height? What is the maximum height?

The rocket reaches its maximum height at ? second(s) after launch.

(Simplify your answer.)

The maximum height reached by the object is ? feet.

(Simplify your answer.)

A toy rocket is shot vertically into the air from a launching pad 7 feet above the ground with an initial velocity of 72 feet

Answer :

Answer:

The rocket reaches its maximum height at 2.25 second(s) after launch.

The maximum height reached by the object is 88 feet.

Step-by-step explanation:

How long will it take the rocket to reach its maximum height?

h(t)=-16t² + 72t +7 is a quadratic equation in the form at²+bt+c, where a=-16 and b=72 and c=7.

The maximum height would be at the vertex / peak of this equation, and we can find the x-coordinate (aka the value of 't') at this point using the formula [tex]\frac{-b}{2a}[/tex]:

[tex]t=\frac{-b}{2a} =\frac{-72}{2(-16)} =\frac{72}{32} =2.25seconds[/tex]

What is the maximum height?

Since we know how long it takes to reach maximum height, we can sub this value into the equation to find our answer:

h(t)=-16t² + 72t +7

h(2.25)=-16(2.25)² + 72(2.25) +7

=-81+162+7=88feet

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Rewritten by : Barada