College

We appreciate your visit to A block of wood weighing 55 0 N is sliding on a surface If a force of 37 1 N is necessary to keep it. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A block of wood weighing 55.0 N is sliding on a surface. If a force of 37.1 N is necessary to keep it sliding at a constant velocity, what is the coefficient of kinetic friction between the wood and the surface?

Answer :

The coefficient of kinetic friction of the wood on the surface is 0.675.

Kinetic friction:

This is the force that acts between two moving surfaces. The magnitude of the force depends on the coefficient of kinetic friction.

To calculate the coefficient of kinetic friction of the wood on the surface, we use the formula below.

⇒ Formula:

  • F = Wμ................ Equation 1

⇒ Where:

  • F = Force needed to keep the block sliding at a constant velocity.
  • W = Weight of the wood
  • μ = coefficient of kinetic friction of the wood on the surface

⇒ Make μ the subject of the equation

  • μ = F/W............... Equation 2

From the question,

⇒ Given:

  • F = 37.1 N
  • W = 55.0 N

⇒ Substitute these values into equation 2

  • μ = 37.1/55
  • μ = 0.675.

Hence, the coefficient of kinetic friction of the wood on the surface is 0.675.

Learn more about friction here: https://brainly.com/question/24338873

Thanks for taking the time to read A block of wood weighing 55 0 N is sliding on a surface If a force of 37 1 N is necessary to keep it. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada