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Answer :
We start with the equation representing the sum of two consecutive numbers. Let the first number be [tex]$n$[/tex], so the second number is [tex]$n+1$[/tex]. The equation is:
[tex]$$
n + (n+1) = 157
$$[/tex]
Combine like terms:
[tex]$$
2n + 1 = 157
$$[/tex]
Subtract [tex]$1$[/tex] from both sides to isolate the term with [tex]$n$[/tex]:
[tex]$$
2n = 157 - 1 = 156
$$[/tex]
Now, divide both sides by [tex]$2$[/tex] to solve for [tex]$n$[/tex]:
[tex]$$
n = \frac{156}{2} = 78
$$[/tex]
Thus, the first number is [tex]$78$[/tex], which corresponds to option B.
[tex]$$
n + (n+1) = 157
$$[/tex]
Combine like terms:
[tex]$$
2n + 1 = 157
$$[/tex]
Subtract [tex]$1$[/tex] from both sides to isolate the term with [tex]$n$[/tex]:
[tex]$$
2n = 157 - 1 = 156
$$[/tex]
Now, divide both sides by [tex]$2$[/tex] to solve for [tex]$n$[/tex]:
[tex]$$
n = \frac{156}{2} = 78
$$[/tex]
Thus, the first number is [tex]$78$[/tex], which corresponds to option B.
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