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Answer :
To find the potential energy of a 25 kg bicycle at the top of a 3 m high hill, we can use the formula for potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's break this down step-by-step:
1. Identify the mass (m):
The bicycle's mass is given as 25 kg.
2. Use the acceleration due to gravity (g):
Gravity is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
3. Identify the height (h):
The height of the hill is 3 m.
4. Plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
5. Perform the multiplication:
- First, multiply the mass and gravity: [tex]\( 25 \times 9.8 = 245 \)[/tex].
- Then, multiply by the height: [tex]\( 245 \times 3 = 735 \)[/tex].
So, the potential energy is 735 J (joules).
Therefore, the correct answer is 735 J.
[tex]\[ PE = m \times g \times h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Let's break this down step-by-step:
1. Identify the mass (m):
The bicycle's mass is given as 25 kg.
2. Use the acceleration due to gravity (g):
Gravity is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
3. Identify the height (h):
The height of the hill is 3 m.
4. Plug these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
5. Perform the multiplication:
- First, multiply the mass and gravity: [tex]\( 25 \times 9.8 = 245 \)[/tex].
- Then, multiply by the height: [tex]\( 245 \times 3 = 735 \)[/tex].
So, the potential energy is 735 J (joules).
Therefore, the correct answer is 735 J.
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