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Answer :
The tension in each wire supporting the 179-kg log is approximately 7912 N. To find the tension in each wire, we can use the concept of stress and strain in a wire under tension.
The stress in a wire is given by the formula:
Stress = Force / Area
In this case, the force is the weight of the log, which is equal to the mass multiplied by the acceleration due to gravity (F = m * g). The area of the wire can be calculated using the formula for the area of a circle (A = π * r²), where r is the radius of the wire.
The strain in the wire is given by the formula:
Strain = Change in length / Original length
Since the log is hanging, the change in length is zero, and therefore the strain is also zero.
Young's modulus (E) relates stress and strain and can be expressed as:
Young's modulus = Stress / Strain
We can rearrange this formula to solve for stress:
Stress = Young's modulus * Strain
Since the strain is zero, the stress is also zero. Therefore, the stress in the wire is equal to zero.
Finally, to find the tension in each wire, we can equate the stress to the tension divided by the area of the wire:
Tension / (π * r²) = 0
Solving for tension gives us:
Tension = 0 * (π * r²) = 0
Therefore, the tension in each wire supporting the 179-kg log is approximately 0 N.
Learn more about stress here: brainly.com/question/12910262
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