High School

We appreciate your visit to A 16 1 kg block is dragged over a rough horizontal surface by a constant force of 96 7 N acting at an angle of. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A 16.1 kg block is dragged over a rough, horizontal surface by a constant force of 96.7 N acting at an angle of 31.7° above the horizontal. The block is displaced 99.9 m, and the coefficient of kinetic friction is 0.216. Find the work done by the 96.7 N force.

The acceleration of gravity is 9.8 m/s². Answer in units of J.

Answer :

Final answer:

The work done by the force is found by multiplying the horizontal component of the applied force with the distance over which the force is applied.

Explanation:

The work done by a force is calculated using the equation W = Fd cos(θ), where W is the work, F is the magnitude of the force applied, d is the distance over which the force is applied, and θ is the angle between the force and the direction of displacement. In this problem, we have a constant force of 96.7 N acting at an angle of 31.7 degrees above the horizontal while the block is displaced 99.9 m. To find the work done by this force, we use the horizontal component of the force, which is F cos(θ) = 96.7 N * cos(31.7 degrees). The calculation gives us the work done by the force.

Thanks for taking the time to read A 16 1 kg block is dragged over a rough horizontal surface by a constant force of 96 7 N acting at an angle of. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada