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Answer :
Final answer:
The molarity of the given solution, based on the provided amounts of magnesium bromide and solution, is calculated to be 0.406 M.
Explanation:
The question is asking to find the molarity of a solution which contains 35.5 g of magnesium bromide in 475 mL of solution. This is a topic rooted in chemistry, specifically concerning the concept of solution concentration.
Molarity is defined as the number of moles of solute per liter of solution. The molecular weight of MgBr2 (magnesium bromide) is approximately 184.11 g/mol. Therefore, the number of moles of magnesium bromide in the solution is 35.5 g ÷ 184.11 g/mol = 0.193 moles. Since molarity is moles per liter, we convert the volume of the solution from mL to L: 475 mL = 0.475 L. Finally, we calculate the molarity by dividing the moles of solute by the liters of solution, which gives us 0.193 moles ÷ 0.475 L = 0.406 M.
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