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Answer :
225.5 kJ of work is needed to stop a 1353 kg car traveling at 93 km/h.
Mass (m) = 1353 kg
Initial velocity (vi) = 93 km/h
= 93 × (5/18) m/s
= 25.83 m/s
Final velocity (vf) = 0 m/s
The work done to stop a car from initial velocity to final velocity is called the work done by frictional force or kinetic friction force.
It is given as, W = f × d
Where,
f = frictional force acting on the car and
d = distance covered by the car during the time it takes to come to rest.
In this case, we can use the formula, W = (1/2) × m × v²
Where,
W = work done by the frictional force acting on the car
m = mass of the car
v = initial velocity of the car.
Here, W = (1/2) × m × v²W = (1/2) × 1353 × (25.83)²W = 225499 J = 225.5 kJ (approx)
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