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Answer :
Final answer:
The net resistance of the light bulb connected to a 6V battery and drawing 2A of current is 3 ohms.
Explanation:
The net resistance of the light bulb can be calculated using Ohm's Law, which states that voltage is equal to current multiplied by resistance. In this case, the voltage is 6V and the current is 2A.Using the formula V = I * R, we can rearrange it to solve for R. So, R = V / I = 6V / 2A = 3 ohms.
Therefore, the net resistance of the light bulb is 3 ohms.
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