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Answer :
Final answer:
The reaction Na2CO3(aq) + CaCl2(aq) -> CaCO3(s) + 2NaCl(aq) releases 39.4 kJ of energy, which is approximately 9.41 kcal when converted using the conversion factor of 1 cal = 4.184 J.
Explanation:
The reaction mentioned Na2CO3(aq) + CaCl2(aq) -> CaCO3(s) + 2NaCl(aq) releases a specified amount of energy, 39.4 kJ. To convert this energy from kilojoules to kilocalories, you would use the energy equivalence between these two units. This equivalence is that 1 cal = 4.184 J. Converting kJ (kilojoules) to J (joules), we multiply by 1000, so 39.4 kJ = 39400 J. Thus, to get the energy in kilocalories, we divide the joules by the conversion factor (4.184 J/cal). So, the reaction releases approximately 9.41 kcal of energy.
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