High School

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In outer space, a constant net force of magnitude 139 N is exerted on a 33.8 kg probe initially at rest.

Options:
A. The probe accelerates at 4.11 m/s²
B. The probe accelerates at 2.57 m/s²
C. The probe accelerates at 6.75 m/s²
D. The probe decelerates at 4.11 m/s²

Answer :

Final answer:

Using Newton's second law, the acceleration of the space probe is calculated by dividing the net force by its mass, resulting in 4.11 m/s².

Explanation:

The student is asking about the acceleration of a space probe when a constant force is applied to it in outer space. To find the acceleration, we use Newton's second law of motion, which states that force equals mass times acceleration (F = ma). Dividing the net force by the mass of the probe gives us the acceleration (a = F/m).

In this case, with a net force of 139 N and a mass of 33.8 kg, the acceleration would be calculated as follows:

a = F/m = 139 N / 33.8 kg = 4.11 m/s²

Therefore, the space probe accelerates at 4.11 m/s², which corresponds to option A.

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