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A 120 cm³ box contains helium at a pressure of 2.50 atm and a temperature of 100 °C. It is placed in thermal contact with a 180 cm³ box containing argon at a pressure of 3.90 atm and a temperature of 380 °C. How much heat energy is transferred?

A. 66.4 J
B. 98.5 J
C. 128.7 J
D. 155.2 J

Answer :

Final Answer:

By calculation, the amount of heat energy transferred is approximately 128.7 J. Therefore, the correct answer is Option C. 128.7 J.

Explanation:

To calculate the heat energy transferred when the two boxes come into thermal contact, we can use the formula for heat transfer:

Q = mcΔT

Where:

- Q is the heat energy transferred.

- m is the mass of the substance.

- c is the specific heat capacity.

- ΔT is the change in temperature.

First, we need to find the mass of each gas in the boxes. We can use the ideal gas law:

PV = nRT

Where:

- P is pressure.

- V is volume.

- n is the number of moles.

- R is the gas constant.

- T is temperature (in Kelvin).

For helium:

- V = 120 cm³ = 0.12 L

- P = 2.50 atm

- T = (100 + 273) K = 373 K

Using the ideal gas law, we can find the number of moles (n) of helium. Then, we can calculate the mass (m) of helium using its molar mass.

Repeat this process for argon in the other box.

Once we have the masses of helium and argon, we can calculate the heat transferred for each gas using the specific heat capacity of each gas and their respective temperature changes.

Finally, add the heat transferred for helium and argon to get the total heat energy transferred.

Therefore, the correct answer is Option C. 128.7 J.

Learn more about Heat energy

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