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A bacterial population doubles every 3 hours. If there were originally 2000 cells in the sample, how many will there be in two days?

Answer :

Final answer:

The bacterial population, which doubles every 3 hours, will grow from 2000 cells to roughly 131,072,000 cells in the span of two days.

Explanation:

In this case, the bacteria are multiplying by two every 3 hours. Given there are 24 hours in a day, that's 8 opportunities for bacteria to double in a day. Therefore, in 2 days, there will be 16 doubling periods.

In mathematical terms, this problem can be addressed using the formula for exponential growth 2^n, where n is the number of doubling periods. Given the initial number of cells is 2000, and the number of times we multiply (or double) is 16, we can express it like this: 2000 * 2^16.

Performing this calculation gives us approximately 131,072,000.

So, after two days, we can expect there to be around 131,072,000 cells in the sample if the population keeps doubling every 3 hours.

Learn more about Exponential Growth here:

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