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Answer :
Let n = the first number. n + 1 = the second and n + 2 = the third number. So....
n + (n + 1) + (n + 2) = 159
3n + 3 = 159
3n = 156
n = 52
n + 1 = 53
n + 2 = 54
So the numbers are 52, 53, and 54.
n + (n + 1) + (n + 2) = 159
3n + 3 = 159
3n = 156
n = 52
n + 1 = 53
n + 2 = 54
So the numbers are 52, 53, and 54.
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Rewritten by : Barada
The middle one is their average, 159/3 = 53.
The numbers are 52, 53, 54.
The numbers are 52, 53, 54.
