Answer :

Answer:

[tex]\displaystyle d = \sqrt{41}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Coordinates (x, y)

Algebra II

  • Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Step-by-step explanation:

Step 1: Define

Point (1, 10)

Point (5, 15)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

  1. Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(5-1)^2+(15-10)^2}[/tex]
  2. [√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{(4)^2+(5)^2}[/tex]
  3. [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{16+25}[/tex]
  4. [√Radical] Add: [tex]\displaystyle d = \sqrt{41}[/tex]

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Rewritten by : Barada