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Answer :
The oscillation of a spring block with mass of 5 kg is described by the equation y = 0.10m cos (2nt). So the spring constant (k) for the given oscillation equation is 5.0 N/m.
In the equation y = A * cos(2πnt), where y is the displacement, A is the amplitude, n is the frequency, and t is time, we can see that the angular frequency (ω) is given by 2πn.
Comparing this with the equation for simple harmonic motion, y = Acos(ωt), we can see that the angular frequency ω is related to the spring constant k and the mass m by the equation ω = √(k/m).
In our given equation, we have ω = 2πn. Since we know the mass of the block is 5 kg, we can solve for k.
k = mω² = (5 kg) * (2πn)² = 5 * 4π²n² = 5 * (39.48n²) = 197.4n².
Therefore, the spring constant k is 197.4n² N/m.
To know more about angular frequency here: brainly.com/question/30897061
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