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Answer :
Final answer:
The 971 kg cart experiences an acceleration of approximately 4.34 m/s^2 as it rounds a corner with a radius of 295 m at a speed of 35.8 m/s.
Explanation:
To answer the question about how much acceleration is experienced by a 971 kg cart that is rounding a corner of radius 295 m traveling at a speed of 35.8 m/s, we must use the concept of centripetal acceleration, which is the force that keeps an object moving in a circular path. The formula for centripetal acceleration is a=(v^2)/r, where 'v' is the speed (velocity) of the object and 'r' is the radius of the circular path.
Substituting the given values into this formula, we get: acceleration = (35.8 m/s)^2/295 m. Performing the calculations gives an acceleration of approximately 4.34 m/s^2 that the cart is experiencing as it rounds the corner.
Learn more about Centripetal Acceleration here:
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