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A piece of unknown metal weighs 217 g. When the metal piece absorbs 1.43 kJ of heat, its temperature increases from 24.5 °C to 39.1 °C. Determine the specific heat of this metal and predict its identity.

Answer :

The specific heat of the metal is 0.389 J/g·°C.

The specific heat of the metal can be calculated using the formula:

q = mcΔT

where q is the heat absorbed, m is the mass of the metal, c is its specific heat, and ΔT is the change in temperature.

Substituting the given values, we get:

1.43 kJ = (217 g) c (39.1 °C - 24.5 °C)

Solving for c, we get:

c = 0.389 J/g·°C

To predict the identity of the metal, we can compare its specific heat to known values for different metals. Based on the calculated specific heat, the metal is likely aluminum or a similar metal with a specific heat close to 0.9 J/g·°C. However, additional tests would be necessary to confirm its identity, such as measuring its melting point, density, and conductivity.

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