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Which line is perpendicular to a line that has a slope of [tex]-\frac{5}{6}[/tex]?

A. line JK
B. line LM
C. line NO
D. line PQ

Answer :

To find a line perpendicular to a given line with a slope of [tex]\(-\frac{5}{6}\)[/tex], we need to determine the negative reciprocal of this slope.

Here's a step-by-step explanation:

1. Understand the Concept of Negative Reciprocal:
- When two lines are perpendicular, the product of their slopes is [tex]\(-1\)[/tex].
- To find a slope that is perpendicular, take the negative reciprocal of the given slope.

2. Calculate the Negative Reciprocal:
- The given slope is [tex]\(-\frac{5}{6}\)[/tex].
- To find the negative reciprocal, first, invert the fraction to get [tex]\(\frac{6}{5}\)[/tex].
- Then, change the sign, so the negative reciprocal becomes [tex]\( \frac{6}{5} \)[/tex].

3. Interpret the Result:
- A line that is perpendicular to a line with a slope of [tex]\(-\frac{5}{6}\)[/tex] will have a slope of [tex]\(\frac{6}{5}\)[/tex].
- Alternatively, [tex]\(\frac{6}{5}\)[/tex] can also be expressed as a decimal, which is [tex]\(1.2\)[/tex].

Therefore, the slope of a line that is perpendicular to the original line with slope [tex]\(-\frac{5}{6}\)[/tex] is [tex]\(1.2\)[/tex]. Now, you can check which of the given lines (line JK, line LM, line NO, or line PQ) has this slope to determine which one is perpendicular to the original line.

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