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Answer :
The magnitude of the elevator's acceleration is 1.63 m/s².
The weight of an object is the force with which it is attracted to the center of the Earth due to gravity. On solid ground, your weight is equal to your mass times the acceleration due to gravity (g), which is approximately 9.81 m/s². Therefore, your mass would be;
mass = weight / g = 151 lb / (9.81 m/s² × 2.2046 lb/kg)
≈ 68.49 kg
In the elevator, your apparent weight is different because the elevator is accelerating. The force acting on you in the elevator is the sum of your weight and the force due to the acceleration of the elevator, which is given by;
force = mass × (g + acceleration)
When the elevator is moving upward with an acceleration a, your apparent weight is;
131 lb = mass × (g + a)
Substituting the value of mass, we get;
131 lb = 68.49 kg × (9.81 m/s² + a)
Solving for a, we get;
a = (131 lb / 68.49 kg - 9.81 m/s²)
≈ 1.63 m/s²
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--The given question is incomplete, the complete question is
"When you weigh yourself on good old terra firma (solid ground), your weight is 151 lb. In an elevator your apparent weight is 131 lb . What is the magnitude of the elevator's acceleration?"--
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