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The director of health services is concerned about a possible flu outbreak at her college. She surveyed 100 randomly selected residents from the college's dormitories to see whether they had received a preventative flu shot. The results are shown below.

What is the probability that a dormitory resident chosen at random from this group has had a flu shot, given that he is male?

Residents at College Dormitories:

[tex]
\[
\begin{tabular}{|c|c|c|c|}
\hline
& \text{Male} & \text{Female} & \text{Total} \\
\hline
\text{Had Flu Shot} & 39 & 41 & 80 \\
\hline
\begin{tabular}{c}
\text{Didn't Have} \\
\text{Flu Shot}
\end{tabular} & 12 & 8 & 20 \\
\hline
\text{Total} & 51 & 49 & 100 \\
\hline
\end{tabular}
\]
[/tex]

Answer :

To solve this problem, we need to calculate the probability that a dormitory resident chosen at random has had a flu shot, given that he is male. We'll use the information provided in the table to find this conditional probability.

Here’s how we can break it down step-by-step:

1. Identify the number of males who had a flu shot:
- From the table, we see that 39 male residents had a flu shot.

2. Identify the total number of males:
- According to the table, there are 51 male residents in total.

3. Calculate the probability:
- The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
- In this case, the probability that a dormitory resident chosen at random has had a flu shot, given that he is male, is the number of males who had a flu shot divided by the total number of males.

[tex]\[
\text{Probability (Had Flu Shot | Male)} = \frac{\text{Number of males who had a flu shot}}{\text{Total number of males}} = \frac{39}{51}
\][/tex]

4. Simplify the fraction (if necessary) or convert it to a decimal:
- When you divide 39 by 51, you get approximately 0.765.

Therefore, the probability that a dormitory resident chosen at random is male and has had a flu shot is approximately 0.765, or 76.5%.

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