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How many moles of nitrogen atoms are there in [tex]1.64 \times 10^{23}[/tex] molecules of dinitrogen trichloride, [tex]N_2Cl_3[/tex]?

Answer :

Final answer:

The number of moles of nitrogen atoms in [tex]1.64 x 10^23[/tex] molecules of dinitrogen trichloride is 0.544 moles, calculated using Avogadro's number and the fact that each molecule contains two nitrogen atoms.

Explanation:

To determine the number of moles of nitrogen atoms in molecules of dinitrogen trichloride (N2Cl3), we use Avogadro's number, which relates the number of particles to moles. Given that Avogadro's number is 6.022 x 1023 mol-1, we can set up a ratio:

Number of moles of N2Cl3 = 1.64 x 1023 molecules / 6.022 x 1023 molecules mol-1 = 0.272 moles of N2Cl3

Each molecule of N2Cl3 contains two nitrogen atoms, so:

Total moles of nitrogen atoms = 0.272 moles of N2Cl3 * 2 = 0.544 moles

Therefore, there are 0.544 moles of nitrogen atoms in 1.64 x 1023 molecules of dinitrogen trichloride.

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Rewritten by : Barada

The number of moles of nitrogen atoms are there in 1.64 x 1023 molecules of dinitrogen trichloride is 0.544.

What are a number of moles?

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

1 mole is 6.022 × 10²³

[tex]1\; molecule = \dfrac{1}{6.023 \times 10^2^3}[/tex]

The given number of moles are 1.64 x 10²³

[tex]1.64 \times 10^2^3= \dfrac{1}{6.023 \times 10^2^3} = 0.272 \\[/tex]

Now, there are two molecules of nitrogen in the dinitrogen trichloride

So, 0.272 x 2 = 0.544

Thus, the number of moles of nitrogen atoms are there in 1.64 x 1023 molecules of dinitrogen trichloride is 0.544.

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