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Karissa begins to solve the equation [tex]\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)[/tex]. Her work is correct and is shown below.

\[
\begin{align*}
\frac{1}{2}(x-14) + 11 & = \frac{1}{2} x - (x - 4) \\
\frac{1}{2} x - 7 + 11 & = \frac{1}{2} x - x + 4 \\
\frac{1}{2} x + 4 & = -\frac{1}{2} x + 4 \\
\end{align*}
\]

When she subtracts 4 from both sides, [tex]\frac{1}{2} x = -\frac{1}{2} x[/tex] results. What is the value of [tex]x[/tex]?

A. -1
B. -\frac{1}{2}
C. 0
D. \frac{1}{2}

Answer :

- Add $\frac{1}{2}x$ to both sides of the equation $\frac{1}{2}x = -\frac{1}{2}x$.
- Simplify the equation to get $x = 0$.
- The value of $x$ that satisfies the equation is 0.
- Final Answer: $\boxed{0}$

### Explanation
1. Understanding the Equation
We are given the equation $\frac{1}{2}x = -\frac{1}{2}x$. Our goal is to find the value of $x$ that satisfies this equation.

2. Solving for x
To solve for $x$, we can add $\frac{1}{2}x$ to both sides of the equation:$$\frac{1}{2}x + \frac{1}{2}x = -\frac{1}{2}x + \frac{1}{2}x$$This simplifies to:$$x = 0$$

3. Final Answer
Therefore, the value of $x$ that satisfies the equation $\frac{1}{2}x = -\frac{1}{2}x$ is 0.

### Examples
This problem demonstrates how to solve a simple algebraic equation. In real life, such equations can model various situations, such as balancing costs and revenues in a business, calculating the required amount of ingredients in a recipe, or determining the equilibrium point in a physical system. Understanding how to solve these equations is fundamental to making informed decisions and solving practical problems.

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Rewritten by : Barada