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Rewrite [tex]$2^x=128$[/tex] as a logarithmic equation.

A. [tex]\log _x 128=2[/tex]
B. [tex]\log _2 x=128[/tex]
C. [tex]\log _2 128=x[/tex]
D. [tex]\log _{128} x=2[/tex]

Answer :

To rewrite the equation [tex]\( 2^x = 128 \)[/tex] as a logarithmic equation, we use the definition of logarithms. In general, the logarithmic form of the equation [tex]\(a^b = c\)[/tex] is [tex]\(\log_a (c) = b\)[/tex].

For the given equation [tex]\(2^x = 128\)[/tex]:

1. The base [tex]\(a\)[/tex] is 2.
2. The exponent [tex]\(b\)[/tex] is [tex]\(x\)[/tex].
3. The value [tex]\(c\)[/tex] is 128.

Using the definition of logarithms, we rewrite [tex]\(2^x = 128\)[/tex] as:

[tex]\[\log_2 (128) = x\][/tex]

Thus, the correct logarithmic form of the equation [tex]\(2^x = 128\)[/tex] is:

[tex]\[\log_2 128 = x\][/tex]

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