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What is the quotient of the following division problem?

[tex]\[ 697 \div 182 = \text{?} \][/tex]

A. 2 r 150
B. 5 r 151
C. 3 r 151
D. 3 r 152

Answer :

To solve the division problem

[tex]$$697 \div 182,$$[/tex]

we first determine how many times [tex]$182$[/tex] can fit into [tex]$697$[/tex].

1. Multiply [tex]$182$[/tex] by [tex]$3$[/tex]:
[tex]$$182 \times 3 = 546.$$[/tex]
2. Multiply [tex]$182$[/tex] by [tex]$4$[/tex]:
[tex]$$182 \times 4 = 728.$$[/tex]

Since [tex]$728$[/tex] is greater than [tex]$697$[/tex], [tex]$182$[/tex] goes into [tex]$697$[/tex] only [tex]$3$[/tex] times. This means the quotient is [tex]$3$[/tex].

3. Next, compute the remainder by subtracting the product of the divisor and quotient from the dividend:
[tex]$$697 - 546 = 151.$$[/tex]

Thus, the result of the division is:

[tex]$$697 \div 182 = 3 \text{ remainder } 151.$$[/tex]

The correct answer is:

[tex]$$\textbf{3 r 151}.$$[/tex]

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