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A centrifugal pump is pumping water at a rate of 35.55 gal/min. The pressures at the inlet and outlet of the pump are -2.26 psig and 7.715 psig respectively. The outlet pipe is placed 10 inches higher than the inlet pipe. The inlet and outlet diameters of the pipe are 1.85 inches and 1.6 inches respectively. The torque produced by the pump rotating at 1593 rpm is 3.172 ft.lbf.

Calculate the following in SI units:

a. Total head

b. Water horsepower (WHP)

c. Shaft horsepower (SHP)

d. Efficiency of the pump

Answer :

a. The total head of the pump is calculated to be 21.113 meters.

b. The water horsepower (WHP) is calculated to be 5.174 kW.

c. The shaft horsepower (SHP) is calculated to be 5.963 kW.

d. The efficiency of the pump is calculated to be 86.68%.

a. To calculate the total head, we need to consider the difference in pressure head, velocity head, and elevation head. The pressure difference between the outlet and inlet is converted to head using the formula: Head = Pressure difference / (density * acceleration due to gravity). The velocity head is calculated using the formula: Head = (velocity^2) / (2 * acceleration due to gravity). The elevation head is calculated by converting the height difference to meters. Adding these three components gives the total head.

b. The water horsepower (WHP) is calculated using the formula: WHP = (Flow rate * Total head) / (The conversion factor). Here, the flow rate is converted to cubic meters per second and the conversion factor is used to convert the units to kilowatts.

c. The shaft horsepower (SHP) is calculated using the formula: SHP = (Torque * Rotational speed) / (The conversion factor). Here, the torque is converted to Newton meters and the conversion factor is used to convert the units to kilowatts.

d. The efficiency of the pump is calculated using the formula: Efficiency = (Water horsepower / Shaft horsepower) * 100%.

Learn more about elevation head here :

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