Objects with masses of 135 kg and 435 kg are separated by 0.500 m. Find the net gravitational force exerted by these objects on a 38.0-kg object placed midway between them.

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Answer :

A1peakenbe A1peakenbe · Answer 1 · 2023-11-07T00:09:49-05:00

Answer:

The net gravitational force on the mass is [tex]1.27\times 10^{-5}[/tex]

Explanation:

We have by Newton's law of gravity the force of attraction between masses [tex]m_{1},m_{2}[/tex]

[tex]F_{att}=G\frac{m_{1}m_{2}}{r^{2}}[/tex]

Applying vales we get

Force of attraction between 135 kg mass and 38 kg mass is

[tex]F_{1}=6.67\times 10^{-11}\frac{135\times 38}{(0.25)^{2}}\\\\F_{1}=5.47\times 10^{-6}N[/tex]

Force of attraction between 435 kg mass and 38 kg mass is

[tex]F_{2}=6.67\times 10^{-11}\frac{435\times 38}{(0.25)^{2}}\\\\F_{2}=1.76\times 10^{-5}N[/tex]

Thus the net force on mass 38.0 kg is [tex]F_{2}-F_{1}=1.76\times 10^{-5}-5.47\times 10^{-6}\\\\F_{2}-F_{1}=1.27\times 10^{-5}[/tex]