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Answer :
To find the mass of iron(III) sulfate [tex]\((Fe_2(SO_4)_3)\)[/tex] produced from the given moles, we need to follow these simple steps:
1. Identify the number of moles of iron(III) sulfate given:
- We have [tex]\(3.21 \times 10^{12}\)[/tex] moles of iron(III) sulfate.
2. Determine the molar mass of iron(III) sulfate:
- The molar mass of [tex]\(Fe_2(SO_4)_3\)[/tex] is given as 399.9 g/mol.
3. Calculate the mass:
- To calculate the mass of iron(III) sulfate produced, multiply the number of moles by the molar mass:
[tex]\[
\text{mass of } Fe_2(SO_4)_3 = (\text{number of moles}) \times (\text{molar mass})
\][/tex]
- Plugging in the values:
[tex]\[
\text{mass of } Fe_2(SO_4)_3 = 3.21 \times 10^{12} \, \text{mol} \times 399.9 \, \text{g/mol}
\][/tex]
4. Result:
- The mass of [tex]\(Fe_2(SO_4)_3\)[/tex] produced is [tex]\(1.28 \times 10^{15}\)[/tex] grams.
Therefore, the correct answer is [tex]\(1.28 \times 10^{15}\)[/tex] g [tex]\(Fe_2(SO_4)_3\)[/tex].
1. Identify the number of moles of iron(III) sulfate given:
- We have [tex]\(3.21 \times 10^{12}\)[/tex] moles of iron(III) sulfate.
2. Determine the molar mass of iron(III) sulfate:
- The molar mass of [tex]\(Fe_2(SO_4)_3\)[/tex] is given as 399.9 g/mol.
3. Calculate the mass:
- To calculate the mass of iron(III) sulfate produced, multiply the number of moles by the molar mass:
[tex]\[
\text{mass of } Fe_2(SO_4)_3 = (\text{number of moles}) \times (\text{molar mass})
\][/tex]
- Plugging in the values:
[tex]\[
\text{mass of } Fe_2(SO_4)_3 = 3.21 \times 10^{12} \, \text{mol} \times 399.9 \, \text{g/mol}
\][/tex]
4. Result:
- The mass of [tex]\(Fe_2(SO_4)_3\)[/tex] produced is [tex]\(1.28 \times 10^{15}\)[/tex] grams.
Therefore, the correct answer is [tex]\(1.28 \times 10^{15}\)[/tex] g [tex]\(Fe_2(SO_4)_3\)[/tex].
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