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a) The acceleration of the system is 2.70 m/s².
b) The force between the 12kg block and the 15kg block is 40.5 Newtons
A) To calculate the acceleration of the system when friction can be ignored
We use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The net force is the applied force of 100.00N.
Total mass of the system:
= 10kg + 15kg + 12kg = 37kg
a = Ft/ Total Mass
a = 100.00N / 37kg ≈ 2.70 m/s²
So, the acceleration of the system is approximately 2.70 m/s².
B) To find the force between the 12kg block and the 15kg block
From Newton's third law of motion, which states that the force between two objects is equal in magnitude and opposite in direction.
The force between the two blocks is the force required to accelerate the 15kg block.
F betweenblocks = Mass* Acceleration
F = 15kg * 2.70 m/s² ≈ 40.5N
So, the force between the 12kg block and the 15kg block is approximately 40.5 Newtons, acting in the opposite direction of the applied force.
Learn more about Newton's laws of motion here
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