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Answer :
Answer:
The average force of wind on the building is 4.728 x 10¹² N
Explanation:
Given;
speed of the air wind, v = 124 km/h
dimension of the building, 42 m wide by 73 m high
density of the air, ρ = 1.3 kg/cm³ =
speed of the air in m/s = 124/3.6 = 34.44 m/s
Area of the building, A = 42 m x 73 m = 3066 m²
density of the air in (k.g/m³);
[tex]\rho = \frac{1.3 \ kg}{cm^3} *(\frac{100\ cm}{1 \ m} )^3\\\\\rho = \frac{1.3 \ kg}{cm^3} *\frac{10^6\ cm^3}{1 \ m^3} = \frac{1.3*10^6 \ kg}{m^3}[/tex]
The average force of wind on the building;
F = mass flow rate x velocity
F = (ρvA) x V
F = ρAv²
F = 1.3 x 10⁶ x 3066 x (34.44)²
F = 4.728 x 10¹² N
Therefore, the average force of wind on the building is 4.728 x 10¹² N
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