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A nurse is preparing to administer mannitol 0.2 g/kg IV bolus over 5 minutes as a test dose to a client who has severe oliguria. The client weighs 198 lbs. What is the amount in grams the nurse should administer?

A) 1.8 g
B) 4.5 g
C) 9.0 g
D) 18.0 g

Answer :

Final answer:

After converting the patient's weight from pounds to kilograms, we calculate the amount of mannitol to be administered by multiplying the patient's weight in kilograms by the dose (0.2 g/kg), resulting in 18.0 g.

Explanation:

The question requires us to determine the amount of mannitol (in grams) a nurse should administer to a client, based on the client's body weight.

Given that the client weighs 198 lbs, first, convert this weight to kilograms as the dosage is written using this unit.

Given that 1 kg = 2.2 lbs, the weight of the patient in kilograms is approximately 90 kg (198 divided by 2.2).

Next, calculate the mannitol dose using the formula provided: 0.2 g/kg.

Therefore, the dosage would be 0.2 * 90 = 18.0 g.

Hence, option D is the correct answer.

Learn more about Medicine Dosage Calculation here:

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