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Answer :
Answer:
C. 0.191 M
Explanation:
Our goal for this question, is to calculate the concentration of the HCl solution. For this, in the experiment, a solution of NaOH was used to find the moles of HCl. Therefore, our first step is to know the reaction between HCl and NaOH:
[tex]HCl~+~NaOH~->~NaCl~+~H_2O[/tex]
The "titrant" in this case is the NaOH solution. If we know the concentration of NaOH (0.100M) and the volume of NaOH (38.2 mL=0.0382 L), we can calculate the moles using the molarity equation:
[tex]M=\frac{mol}{L}[/tex]
[tex]0.100~M=\frac{mol}{0.0382~L}[/tex]
[tex]mol=0.100~M*0.0382~L=0.0382~mol~of~NaOH[/tex]
Now, in the reaction, we have a 1:1 molar ratio between HCl and NaOH (1 mol of HCl is consumed for each mole of NaOH added). Therefore we will have the same amount of moles of HCl in the solution:
[tex]0.0382~mol~of~NaOH\frac{1~mol~HCl}{1~mol~NaOH}=0.0382~mol~HCl[/tex]
If we want to calculate the molarity of the HCl solution we have to divide by the litters of HCl used in the experiment (20 mL= 0.02 L):
[tex]\frac{0.0382~mol~HCl}{0.02~L}~=~0.191~M[/tex]
The concentration of the HCl solution is 0.191 M
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Rewritten by : Barada
The concentration of the HCl solution is calculated using the volume and molarity of the NaOH titrant. Given the titration data, the molarity of the HCl is determined to be 0.191 M.
To determine the concentration of the HCl solution, we can use the titration data provided. The chemical reaction between HCl and NaOH is a one-to-one reaction, meaning one mole of HCl reacts with one mole of NaOH:
HCl + NaOH → NaCl + H₂O
Given the average volume of the titrant (NaOH) used is 38.2 mL (or 0.0382 L) and its concentration is 0.100 M, we calculate the moles of NaOH used in the reaction:
Moles of NaOH = Volume (L) * Concentration (M)
= 0.0382 L * 0.100 M
= 0.00382 mol
Since the reaction ratio is 1:1, the moles of HCl that reacted are also 0.00382 mol. To find the molarity of the HCl solution:
Molarity (M) = Moles of solute (mol) / Volume of solution (L)
The starting volume of the HCl solution was 20 mL (or 0.020 L). Therefore:
Molarity of HCl = 0.00382 mol / 0.020 L
= 0.191 M
Thus, the concentration of the HCl is 0.191 M, which corresponds to option C.
