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Answer :
Final answer:
To determine the mass of 0.25 mole of Al2(CrO4)3, first calculate its molar mass (401.96 g/mol) and then find 25% of this mass, yielding 100.49 g, which rounds to 100.5 g.
Explanation:
To find the mass of 0.25 mole of Al2(CrO4)3, we first need to calculate the molar mass of Al2(CrO4)3. The molar mass is the sum of the atomic masses of all atoms in the formula. Looking at the periodic table, the atomic masses are approximately Al (26.98 g/mol), Cr (52.00 g/mol), and O (16.00 g/mol).
Molar mass of Al2(CrO4)3 = (2*26.98) + (3*52.00) + (12*16.00) = 53.96 + 156 + 192 = 401.96 g/mol.
Therefore, the mass of 0.25 mole of Al2(CrO4)3 = 0.25 * 401.96 g/mol = 100.49 g. Thus, the closest answer is C) 100.5 g.
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