Answer :

Let's go through the process of writing the nuclear equation for the beta decay of Cerium-141 step-by-step:

### Step 1: Understand Beta Decay
Beta decay is a type of radioactive decay in which a neutron in the nucleus is converted into a proton and an electron (beta particle) is emitted. As a result:
- The atomic number increases by 1 (because one neutron turns into a proton).
- The mass number remains unchanged (since the total number of nucleons stays the same).

### Step 2: Information About Cerium-141
- Cerium (Ce) has an atomic number of 58.
- The mass number of Cerium-141 is 141.

### Step 3: Determine the Resulting Element
- When Cerium-141 undergoes beta decay, it converts into an element with an atomic number increased by 1.
- The new atomic number will be 58 + 1 = 59.
- The element with atomic number 59 is Praseodymium (Pr).

### Step 4: Write the Nuclear Equation
The nuclear equation for the beta decay of Cerium-141 can be written as follows:
[tex]\[
\overset{141}{58}\text{Ce} \rightarrow \overset{141}{59}\text{Pr} + \overset{0}{-1}\text{e}
\][/tex]

This equation shows that Cerium-141 decays into Praseodymium-141, emitting a beta particle (an electron).

### Final Answer
The nuclear equation for the beta decay of Cerium-141 is:

[tex]\[
\overset{141}{58}\text{Ce} \rightarrow \overset{141}{59}\text{Pr} + \overset{0}{-1}\text{e}
\][/tex]

This equation confirms the transformation of a neutron into a proton within the nucleus of Cerium-141, resulting in the emission of a beta particle and the formation of Praseodymium-141.

Thanks for taking the time to read Write the nuclear equation for the beta decay of cerium 141. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada