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**1-D Kinematics**

A plane flies with an average velocity of [tex]-98.5 \, \text{m/s}[/tex] for 45.0 s.

What was its displacement?

[tex]\Delta x = \, [?] \, \text{m}[/tex]

Answer :

To find the displacement of the plane, we can use the formula for displacement when average velocity and time are known:

[tex]\[
\Delta x = v \times t
\][/tex]

Where:
- [tex]\(\Delta x\)[/tex] is the displacement.
- [tex]\(v\)[/tex] is the average velocity.
- [tex]\(t\)[/tex] is the time.

In this problem, the average velocity [tex]\(v\)[/tex] is [tex]\(-98.5 \, \text{m/s}\)[/tex] and the time [tex]\(t\)[/tex] is [tex]\(45.0 \, \text{s}\)[/tex].

Now, let's calculate the displacement:

[tex]\[
\Delta x = (-98.5 \, \text{m/s}) \times (45.0 \, \text{s})
\][/tex]

[tex]\[
\Delta x = -4432.5 \, \text{m}
\][/tex]

So, the displacement of the plane is [tex]\(-4432.5\)[/tex] meters. The negative sign indicates that the displacement is in the opposite direction of the positive reference direction.

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