To determine the power in kW required to pump 50 m³ of water in 15 minutes against a head of 5 m with a pump efficiency of 60%, follow these steps:

1. **Calculate the flow rate (Q) in m³/s:**
- Total volume = 50 m³
- Time = 15 minutes = 900 seconds
- Flow rate \( Q = \frac{50 \text{ m}^3}{900 \text{ s}} = \frac{1}{18} \text{ m}^3/\text{s} \)

2. **Calculate the power using the formula:**
- Power = \(\frac{Q \times p \times g \times H}{\eta}\)
- Where:
- \( Q \) is the flow rate in m³/s
- \( p \) is the density of water (approximately 1000 kg/m³)
- \( g \) is the acceleration due to gravity (approximately 9.81 m/s²)
- \( H \) is the head in meters (5 m)
- \( \eta \) is the pump efficiency (60% or 0.60)

3. **Plug in the values:**
- Power = \(\frac{\left(\frac{1}{18}\right) \times 1000 \times 9.81 \times 5}{0.60}\)

4. **Calculate the power:**
- Power ≈ 4.54 kW

Thus, the power required to pump 50 m³ of water in 15 minutes against a head of 5 m with a pump efficiency of 60% is approximately 4.54 kW.