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A 6 ohm, 5 ohm, and 8 ohm resistor are connected in series with a 30 V battery. What is the total resistance, and what is the current through the 8 ohm resistor?

Answer :

To calculate the total resistance and current through the 8 ohm resistor in a series circuit with a 30 V battery and resistors with values of 6 ohms, 5 ohms, we can use for calculating total resistance in a series circuit.

How to calculate total resistance ?

  • The formula for total resistance in a series circuit is:

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Rtotal = R1 + R2 + R3 + ...

where R1, R2, R3, etc. are the individual resistance values.

  • Using this formula, we can calculate the total resistance of the circuit as:

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Rtotal = 6 ohms + 5 ohms + 8 ohms

Rtotal = 19 ohms

  • To calculate the current through the 8 ohm resistor, we can use Ohm's Law, which states that the current (I) through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor:

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I = V / R

  • In this case, the voltage across the entire series circuit is 30 V, and the resistance of the 8 ohm resistor is 8 ohms. So we can calculate the current through the 8 ohm resistor as:

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I = V / R

I = 30 V / 19 ohms

I = 1.58 A (rounded to two decimal places)

Therefore, the total resistance of the circuit is 19 ohms, and the current through the 8 ohm resistor is 1.58 A.

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