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Answer :
Answer: a) 783 ways; b) 593775 ways
Step-by-step explanation:
a) Your friend wants to select 3 zinfandel out of 9 from the supply in a particular order, which means:
[tex]P_{n,r} = \frac{n!}{(n-r)!}[/tex]
[tex]P_{9,3} = \frac{9!}{(9 - 3)!}[/tex]
[tex]P_{9,3} = \frac{9.8.7.6!}{6!}[/tex]
[tex]P_{9,3}[/tex] = 783
In the dinner party, the friend will have 783 ways of serving the zinfandel.
b) Now, your friend want to select 6 bottles out of 30 in no particular order and randomly selected. So:
[tex]C_{n,r} = \frac{n!}{r!(n - r)!}[/tex]
[tex]C_{30,6} = \frac{30!}{6!.24!}[/tex]
[tex]C_{30,6} = \frac{30.29.28.27.26.25.24!}{6.5.4.3.2.1.24!}[/tex]
[tex]C_{30,6}[/tex] = 593775
If you select 6 bottles randomly from 30, you will have 593775 ways of doing it.
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