College

We appreciate your visit to A roller coaster with a potential energy of tex 235 200 J tex sits at the top of a 30 m high hill What is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A roller coaster with a potential energy of [tex]$235,200 J$[/tex] sits at the top of a 30 m high hill. What is the mass of the roller coaster?

(Formula: [tex]$PE = mgh$[/tex])

A. 800 kg
B. [tex]$7,840 kg$[/tex]
C. [tex]$8,000 kg$[/tex]
D. [tex]$78,400 kg$[/tex]

Answer :

To find the mass of the roller coaster, we can use the formula for potential energy:

[tex]\[ \text{Potential Energy (PE)} = m \cdot g \cdot h \][/tex]

where:
- [tex]\( \text{PE} \)[/tex] is the potential energy in joules,
- [tex]\( m \)[/tex] is the mass in kilograms,
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.81 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height in meters.

Given:
- [tex]\(\text{PE} = 235,200 \, \text{Joules}\)[/tex]
- [tex]\( h = 30 \, \text{meters} \)[/tex]
- [tex]\( g = 9.81 \, \text{m/s}^2 \)[/tex]

We want to solve for [tex]\( m \)[/tex], so we rearrange the formula:

[tex]\[ m = \frac{\text{PE}}{g \cdot h} \][/tex]

Substitute the given values into the formula:

[tex]\[ m = \frac{235,200}{9.81 \times 30} \][/tex]

[tex]\[ m = \frac{235,200}{294.3} \][/tex]

[tex]\[ m = 799.1845056065239 \][/tex]

The mass of the roller coaster is approximately [tex]\( 800 \, \text{kg} \)[/tex].

Therefore, the correct answer is [tex]\( 800 \, \text{kg} \)[/tex].

Thanks for taking the time to read A roller coaster with a potential energy of tex 235 200 J tex sits at the top of a 30 m high hill What is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada