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By what percent does the braking distance of a car decrease when the speed of the car is reduced by 10.3%?

(Note: Braking distance is the distance a car travels from the point when the brakes are applied to when the car comes to a complete stop.)

**Hint:** It's not 10.3%.

Answer :

The percentage decrease in the braking distance of the car is 19.5%.

Distance traveled by the car

v² = u² + 2as

where;

  • v is final velocity when brake is applied
  • u is initial velocity
  • s is distance traveled

s = (v² - u²)/(2a)

v = 100%u - 10.3%u = 89.7% u = 0.897u

s = [(0.897u)² - u²]/(2a)

s = -0.195u²/2a

percent decrease = 0.195 x 100% = 19.5%

Thus, the percentage decrease in the braking distance of the car is 19.5%.

Learn more about braking distance here: https://brainly.com/question/4085091

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