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Answer :
To find the charge of a lead ion with 82 protons and 80 electrons, we need to understand how ion charge is determined.
1. Understand the Structure of an Atom:
- Protons carry a positive charge (+1 each).
- Electrons carry a negative charge (-1 each).
- Neutrons are neutral and don't affect the charge.
2. Determine the Charge on Protons and Electrons:
- The charge due to 82 protons is [tex]\( +82 \)[/tex].
- The charge due to 80 electrons is [tex]\( -80 \)[/tex].
3. Calculate the Ion Charge:
- The charge of the ion is the total charge from protons minus the total charge from electrons.
- Therefore, the charge of the ion can be calculated as:
[tex]\[
\text{ion charge} = \text{protons} - \text{electrons} = 82 - 80
\][/tex]
4. Result:
- By performing the subtraction, we find:
[tex]\[
\text{ion charge} = 2
\][/tex]
- This means the ion has a positive charge of +2.
5. Conclusion:
- The equation to determine the ion charge is [tex]\((B)\)[/tex] [tex]\( \text{ion charge} = 82 - 80 \)[/tex].
Therefore, the correct equation to find the charge of the ion is option (B). The charge of the ion is [tex]\( +2 \)[/tex].
1. Understand the Structure of an Atom:
- Protons carry a positive charge (+1 each).
- Electrons carry a negative charge (-1 each).
- Neutrons are neutral and don't affect the charge.
2. Determine the Charge on Protons and Electrons:
- The charge due to 82 protons is [tex]\( +82 \)[/tex].
- The charge due to 80 electrons is [tex]\( -80 \)[/tex].
3. Calculate the Ion Charge:
- The charge of the ion is the total charge from protons minus the total charge from electrons.
- Therefore, the charge of the ion can be calculated as:
[tex]\[
\text{ion charge} = \text{protons} - \text{electrons} = 82 - 80
\][/tex]
4. Result:
- By performing the subtraction, we find:
[tex]\[
\text{ion charge} = 2
\][/tex]
- This means the ion has a positive charge of +2.
5. Conclusion:
- The equation to determine the ion charge is [tex]\((B)\)[/tex] [tex]\( \text{ion charge} = 82 - 80 \)[/tex].
Therefore, the correct equation to find the charge of the ion is option (B). The charge of the ion is [tex]\( +2 \)[/tex].
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