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Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a [tex]\checkmark[/tex] chance that the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

2. If a heterozygous [tex]WW[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & WW \\
\hline W & WW & WW \\
\hline
\end{array}
\]
[/tex]

Answer :

Sure! Let's break this down step-by-step.

### Part 1: Heterozygous male (Ww) and homozygous recessive female (ww)

1. Parent Genotypes:
- Male: Ww (heterozygous)
- Female: ww (homozygous recessive)

2. Possible Offspring Genotypes:
- From the male (Ww), possible alleles are W and w.
- From the female (ww), the allele is w.

3. Punnett Square:
```
| | W | w |
|----|-----|-----|
| w | Ww | ww |
| w | Ww | ww |
```

4. Genotype Outcomes:
- Ww (heterozygous): 2 occurrences
- ww (homozygous recessive): 2 occurrences

5. Probability:
- The chance of an offspring being heterozygous (Ww) is 2 out of 4 possibilities, which equals 0.5 or 50%.

### Part 2: Homozygous dominant (WW) crossed with another homozygous dominant (WW)

1. Parent Genotypes:
- First Parent: WW (homozygous dominant)
- Second Parent: WW (homozygous dominant)

2. Possible Offspring Genotypes:
- From both parents, the allele is W.

3. Punnett Square:
```
| | W | W |
|----|-----|-----|
| W | WW | WW |
| W | WW | WW |
```

4. Genotype Outcomes:
- WW (homozygous dominant): All offspring are WW

5. Probability:
- The probability of having a homozygous recessive offspring (ww) is 0 out of 4 possibilities, which equals 0.0 or 0%.

So, based on this analysis:

- First part: There is a 0.5 or 50% chance that the offspring will be heterozygous (Ww).
- Second part: There is a 0.0 or 0% probability of getting a homozygous recessive (ww) offspring when crossing WW with WW.

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