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Answer :
The acceleration of the car is 4.00 m/s^2. So, the answer is option A.
What is Speed?
Speed is a measure of how fast an object is moving, usually expressed in units of distance per unit time, such as meters per second (m/s) or miles per hour (mph). It is a scalar quantity, meaning it has magnitude but no direction.
The acceleration of the car can be found using the equation:
acceleration = (final velocity - initial velocity) / time
Plugging in the given values, we get:
acceleration = (30.0 m/s - 10.0 m/s) / 5.00 s
acceleration = 20.0 m/s / 5.00 s
acceleration = 4.00 m/s^2
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The acceleration of the car is calculated using the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time interval. The calculated acceleration is 4.00 m/s², making the correct answer A: 4.00 m/s².
The question asks about the acceleration of a car that increases its velocity from 10.0 m/s to 30.0 m/s over a period of 5.00 seconds. To find this, we use the formula for acceleration given by:
a = (vf - vi) / t
where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time taken for the change in velocity. Substituting the given values:
a = (30.0 m/s - 10.0 m/s) / 5.00 s
a = 20.0 m/s / 5.00 s
a = 4.00 m/s²
Therefore, the correct answer is A: 4.00 m/s².
