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An acre measures 4840 square yards. In a city, a lot on which a single-family house can be built measures 40 feet across and 100 feet deep.

What percent of an acre is this lot?

Answer :

The lot is 9.2% of the an acre.

Given:

Area of an acre = 4840 sq. yards

Area of lot = 40 by 100 ft = [tex]40 ]\times 100 = 4,000 $ ft^{2}[/tex]

To determine the the percentage of the acre of land that the lot will occupy, we would do the following:

  • Convert the area of lot to square feet
  • Find the area of the lot
  • Then, calculate the percentage of the area of the lot it occupies in an acre of land

Thus:

Convert the area of the lot to feet ([tex]9 ft^{2} = 1yd^{2}[/tex]):

Therefore:

Area of lot = [tex]\frac{4,000}{9} = 444.4 $ yd^{2}[/tex]

Percentage occupied by the lot = area of lot / area of acre x 100

[tex]= \frac{444.4}{4840} \times 100\\\= 9.2[/tex]

The lot therefore is 9.2% of the an acre.

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https://brainly.com/question/20730855

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