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If the number of bacteria in a colony doubles every 203 minutes and there is currently a population of 40 bacteria, what will the population be 812 minutes from now?

Answer :

Final answer:

In a doubling time scenario where the bacteria population doubles every 203 minutes, after 812 minutes the population will have grown from 40 to 640 bacteria.

Explanation:

This is a problem of exponential growth, more specifically a problem dealing with the mathematical concept of doubling time. The doubling time is the amount of time it takes for a quantity to double in size or value. In this case, the doubling time is 203 minutes, which is the time it takes for the bacteria population to double.

To find the population of bacteria after a certain time, we use the formula:

N = N0 * 2^(t / T)

Where:

  • N0 is the initial quantity (the current bacteria population, which is 40),
  • t is the time elapsed (812 minutes),
  • T is the doubling time (203 minutes),
  • N is the final quantity (the bacteria population we are trying to find).

Filling in the numbers, we get:

N = 40 * 2^(812 / 203)

Calculating this, the population will be 640 bacteria after 812 minutes.

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Rewritten by : Barada

Answer:

640 Bacteria

Step-by-step explanation:

First, find out how many times the population will double. Divide the number of minutes by how long it takes for the population to double.

812÷203=4

The population will double 4 times.

Now figure out what the population will be after it doubles 4 times. Multiply the population by 2 a total of 4 times.

402222=640

That calculation could also be written with exponents:

4024=640

After 812 minutes, the population will be 640 bacteria.