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The water main at my house has a pressure of 135 psig. If a nozzle with a diameter of 0.5 inches is attached to the main, what is the maximum flow rate at which water would leave the nozzle?

A. 11.4 gpm
B. 43.8 gpm
C. 29.5 gpm
D. 61.3 gpm

Answer :

Answer:

Q = 86.38 gpm

Explanation:

pressure in house = 135 psig

1 psig = 6894.76 pa

= 135 × 6894.76 pa = 930792 pa

P = ρ g h

[tex]h =\dfrac{P}{\rho g}[/tex]

[tex]h =\dfrac{930792}{1000\times 9.81}[/tex]

h = 94.88 m

velocity at the exit of nozzle

[tex]v=\sqrt{2gh} \\v=\sqrt{2\times 9.81 \times 94.88}\\v = 43.15 m/s[/tex]

discharge (Q) = Av

= [tex]\dfrac{\pi}{4}d^2\times v[/tex]

= [tex]\dfrac{\pi}{4}0.0127^2\times43.15\\5.45\times 10^{-3}[/tex]

Q = 86.38 gpm

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