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Answer :
Final answer:
The maximum torque on the square loop of wire is 1482.864 Nm.
Explanation:
The maximum torque on a current-carrying loop of wire can be calculated using the formula T = NIAB sin θ. In this case, the loop has 181 turns, a side length of 18.0 cm, and carries a current of 51.0 A in a magnetic field of 1.60 T.
First, we need to calculate the area of the loop. The loop is square, so the area is given by A = (side length)^2. Plugging in the values, we get A = (0.18 m)^2 = 0.0324 m^2.
Next, we can calculate the torque using the formula. T = (181)(51.0 A)(0.0324 m^2)(1.60 T) sin 90° = 1482.864 Nm
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