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Answer :
To solve the inequality [tex]\(x + 22 < 32\)[/tex], we want to find all the values of [tex]\(x\)[/tex] that will make this inequality true.
Step 1: Isolate [tex]\(x\)[/tex]:
Start by subtracting 22 from both sides of the inequality:
[tex]\[ x + 22 - 22 < 32 - 22 \][/tex]
This simplifies to:
[tex]\[ x < 10 \][/tex]
Step 2: Check each option:
Now we know that [tex]\(x\)[/tex] should be less than 10. Let's check each option to see which numbers satisfy this condition:
- A. 10: 10 is not less than 10.
- B. 8: 8 is less than 10.
- C. 5: 5 is less than 10.
- D. 71: 71 is not less than 10.
- E. 15: 15 is not less than 10.
- F. 0: 0 is less than 10.
Conclusion:
The numbers that satisfy the inequality [tex]\(x < 10\)[/tex] from the given options are 8, 5, and 0. Therefore, the solution set is: B. 8, C. 5, F. 0.
Step 1: Isolate [tex]\(x\)[/tex]:
Start by subtracting 22 from both sides of the inequality:
[tex]\[ x + 22 - 22 < 32 - 22 \][/tex]
This simplifies to:
[tex]\[ x < 10 \][/tex]
Step 2: Check each option:
Now we know that [tex]\(x\)[/tex] should be less than 10. Let's check each option to see which numbers satisfy this condition:
- A. 10: 10 is not less than 10.
- B. 8: 8 is less than 10.
- C. 5: 5 is less than 10.
- D. 71: 71 is not less than 10.
- E. 15: 15 is not less than 10.
- F. 0: 0 is less than 10.
Conclusion:
The numbers that satisfy the inequality [tex]\(x < 10\)[/tex] from the given options are 8, 5, and 0. Therefore, the solution set is: B. 8, C. 5, F. 0.
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